




Rx = Vx / Ix 

Rx = R0 V2 / V1 
The AC version of the bridge, with attendant vectors is shown
on the right. In order to analyse this network, we first observe
that V1+V2
must be equal to V0+Vx, and that the voltage across the detector
D (Vdet) is equal to both V1V0 and VxV2, i.e., V0 + Vx = V1 + V2 Vdet = V1  V0 Vdet = Vx  V2 

Zx = Z0 V2 / V1 
Zx = ( R0 + j X0 ) V2 / V1 
Zx = ( R0 + j X0 ) V2 / V1 
Zx = ( R0 + j X0 ) 
X2 / R2 = X1 / R1 